6-[3x-(2+x)]=4(x-1)

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Solution for 6-[3x-(2+x)]=4(x-1) equation:


Simplifying
6 + -1[3x + -1(2 + x)] = 4(x + -1)
6 + -1[3x + (2 * -1 + x * -1)] = 4(x + -1)
6 + -1[3x + (-2 + -1x)] = 4(x + -1)

Reorder the terms:
6 + -1[-2 + 3x + -1x] = 4(x + -1)

Combine like terms: 3x + -1x = 2x
6 + -1[-2 + 2x] = 4(x + -1)
6 + [-2 * -1 + 2x * -1] = 4(x + -1)
6 + [2 + -2x] = 4(x + -1)

Combine like terms: 6 + 2 = 8
8 + -2x = 4(x + -1)

Reorder the terms:
8 + -2x = 4(-1 + x)
8 + -2x = (-1 * 4 + x * 4)
8 + -2x = (-4 + 4x)

Solving
8 + -2x = -4 + 4x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4x' to each side of the equation.
8 + -2x + -4x = -4 + 4x + -4x

Combine like terms: -2x + -4x = -6x
8 + -6x = -4 + 4x + -4x

Combine like terms: 4x + -4x = 0
8 + -6x = -4 + 0
8 + -6x = -4

Add '-8' to each side of the equation.
8 + -8 + -6x = -4 + -8

Combine like terms: 8 + -8 = 0
0 + -6x = -4 + -8
-6x = -4 + -8

Combine like terms: -4 + -8 = -12
-6x = -12

Divide each side by '-6'.
x = 2

Simplifying
x = 2

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